3(x-5)+3y^2=27

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Solution for 3(x-5)+3y^2=27 equation:


Simplifying
3(x + -5) + 3y2 = 27

Reorder the terms:
3(-5 + x) + 3y2 = 27
(-5 * 3 + x * 3) + 3y2 = 27
(-15 + 3x) + 3y2 = 27

Solving
-15 + 3x + 3y2 = 27

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 3x + 15 + 3y2 = 27 + 15

Reorder the terms:
-15 + 15 + 3x + 3y2 = 27 + 15

Combine like terms: -15 + 15 = 0
0 + 3x + 3y2 = 27 + 15
3x + 3y2 = 27 + 15

Combine like terms: 27 + 15 = 42
3x + 3y2 = 42

Add '-3y2' to each side of the equation.
3x + 3y2 + -3y2 = 42 + -3y2

Combine like terms: 3y2 + -3y2 = 0
3x + 0 = 42 + -3y2
3x = 42 + -3y2

Divide each side by '3'.
x = 14 + -1y2

Simplifying
x = 14 + -1y2

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